tinsle testing
I can figure out how much pulling force can be aplied to an aluminum dogbone.
starting out
First we start out with a 3.5 inches long aluminum rod. Then we have to use a lathe to trim a 1 inches long section in the center of the rod. we make the diameter about 0.125 inches thick. After that, we cut off a certain amount of aluminum off each end so the total end length is 3 inches long so it could fit in the testing machine. then we had to clean off both ends of the rod so that it would screw in with ease.
testing the dogbone
the tester pulled on both ends of the dog bone. the pulling of it had caused deformation and stretched the thin part in the middle until it reached its maximum length of elongation, until it broke. After the tester pulled the dog bone in half and all of the data was recorded, I remeasured the dog bone. The length of the lathed part of the dog bone started out as 1 inch and was 1.103 inches after breaking and the diameter of it started out as 0.125 inches and ended up as 0.106 inches. The sample rod broke at 619 lbs.
results of testing
The rods total strain/deformation, which is the total amount of the elongation of the rod to rupture divided by the original length was 0.996.
etotal(strain)=stress/original length=0.996
The rods ductility, which is the ability to be deformed plastically without breaking was 99.6%. Plastic elongation is the unrecoverable elongation beyond the elastic limit.
% of Elongation = etotal (100) = 99.6%
The rods reduction in area which can be found by subtracting the final area from the original area and dividing the difference by the original area multiplied by 100 was 0.004 inches.
Reduction in area = (A original – A final)/A original*100
Proportional Limit Stress = F/A = 45,528 PSI
Maximum Tensile Stress = F/A = 41,635 PSI
Ultimate/Tensile Stress = F/A = 38,618 PSI
Modulus of Elasticity = F/A = 31,111 PSI
etotal(strain)=stress/original length=0.996
The rods ductility, which is the ability to be deformed plastically without breaking was 99.6%. Plastic elongation is the unrecoverable elongation beyond the elastic limit.
% of Elongation = etotal (100) = 99.6%
The rods reduction in area which can be found by subtracting the final area from the original area and dividing the difference by the original area multiplied by 100 was 0.004 inches.
Reduction in area = (A original – A final)/A original*100
Proportional Limit Stress = F/A = 45,528 PSI
Maximum Tensile Stress = F/A = 41,635 PSI
Ultimate/Tensile Stress = F/A = 38,618 PSI
Modulus of Elasticity = F/A = 31,111 PSI